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OlgaM077 [116]
3 years ago
7

Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on

seven-point touchdowns and some on three-point field goals. The 80 scores accounted for 516 points. How many touchdowns and field goals did they score
Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

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G(x) = 15 – 4x<br> h(x) = x +8<br> Write g(h(x)) as an expression in terms of 2.
Sergeu [11.5K]

For this case we have the following functions:

g (x) = 15-4x\\h (x) = x + 8

We must findg (h (x))when x = 2.

So:

g (h (x)) = 15-4 (x + 8) =

We apply distributive property to the terms within parentheses taking into account that:

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We add similar terms taking into account that different signs are subtracted and the sign of the major is placed:

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Thus, we have to:

g (h (x)) = - 17-4x

Then, with x = 2:

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g (h (2)) = - 25

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3 years ago
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Rewriting the left-hand side as follows,

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Answer:

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one side of a square is 10 units. which is greater,the number of square units for the area of the square or the number of units
user100 [1]
Hello Shaffer23,
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~Naterator
Please Thank and Rate If This Is Helpful <3
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