Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: "A rectangular yard is 20 ft by 15 ft. The yard is cover with grass except for 8.5 feet square flower garden. How much grass is in the yard?"</h3><h3 />
The area of a rectangle can be calculated with the following formula:

Where "l" is the lenght of the rectangle and "w" is the width.
Based on the data given in the exercise, you can identify tha the length and the width of the rectangular yard are:

Then, you can substitute these values into the formula and then evaluate in order to find the area of the entire yard:

The area of the flower garden which is an square, can be calculated with this formula:

Where "s" is the side length.
In this case you know that:

Then the area of the flower garden is:

<em> </em>Since this is not covered with grass, you need to subtract both areas calculated above in order to find the surface covered with grass in the yard.
This is:

Alright, I'll explain them as well.
1. The answer is 7, The open end of the sign is always to the larger number.
2. The answer is 4, and again, the open end of the sign is always to the bigger number.
3. The answers is two, and as before, 2 is the only number that will not make it negative or 0 and make the larger number be to the open end of the sign.
4. I'm not entirely sure on this one, so I won't answer it because I don't want to be the reason you get it incorrect.
5. For this one, divide 180 by 2.25, this will give you 80. The inequality should be 2.25k ≥ 180, k <span>≥ 80.
I hope this helps, have a nice day :)</span>
Solve (x) F(x)=x^2+3x-2 is x-2
Y = 2/3x - 2....the y int here is -2
and u want a line with a slope of -2/3 and a y int of -2...
y = -2/3x - 2.....so u have a slope of -2/3 (means ur line is decreasing)....and a y int of -2...means ur line crosses the y axis at (0,-2)
ur x int can be found by subbing in 0 for y and solving for x
0 = -2/3x - 2
2/3x = -2
x = -2 * 3/2
x = - 3.....and u have an x int(where ur line crosses the x axis) at (-3,0)
so ur graph for this is : the 4th graph...the last one