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Natali5045456 [20]
3 years ago
15

“Tom needs to order some hamburgers for his colleagues. Each hamburger costs $2.00, and the delivery fee is a flat $5.00 no matt

er how many hamburgers he orders. If Tom's order came to a total of $25, how many hamburgers did he order?”
Mathematics
2 answers:
3241004551 [841]3 years ago
7 0

Answer:

10

There is no explanation I used a calculator

Alja [10]3 years ago
7 0
10 it is quick maths any more questions
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Which of the following have a infinite number of solutions?
Dominik [7]
A) 3x-3= -4x has ONE solution.

B) 2y+4-y=16 has ONE solution.

C) 7x+5=4x+5+3x has INFINITE solutions.

D) 6y-2=2(y-1) has ONE solution.

Your answer is C) considering that it has an infinite number of solutions.
5 0
3 years ago
Thank you for helping if you do :D
choli [55]
This one is side side side since all the sides are congruent on both triangles
the answer is SSS
8 0
3 years ago
Susan is taking Western Civilization this semester on a pass/fail basis. The department teaching the course has a history of pas
Volgvan

Answer:

a. P(n) = 0.85 * (0.15)^(n-1)

b. P(n=1) = 0.85

c. P(n= 2) = 0.1275

d. P(n≥3) = 0.0225

e. Expected number of attempts is 1.176

Step-by-step explanation:

a.

Given

p = success = 85% = 0.85

q = failure = 1 - q = 1 - 0.85 = 0.15

The results of passing/failing takes a Bernoulli distribution

Since, there are independent trials

The number of trials until the first successful event occurs is given by

P(n = k) = p . (1 - p)^(k-1)

P(n = k) = p.q^(k-1)

This is so because it is a Bernoulli distribution and it is modeled by a geometric distribution.

Substitute 0.85 for p

P(n) = 0.85 * (0.15)^(n-1)

b.

Given

n = 1

Using P(n=1) = 0.85 * (0.15)^(n-1)

P(1) = 0.85 * 0.15^(1-1)

P(1) = 0.85 * 0.15°

P(1) = 0.85 * 1

P(1) = 0.85

Therefore, the probability that Susan passes on the first try is 0.85.

c.

n = 2

Using P(n=2) = 0.85 * (0.15)^(2-1)

P(2) = 0.85 * 0.15^(2-1)

P(2) = 0.85 * 0.15¹

P(2) = 0.85 * 0.15

P(2) = 0.1275

Therefore, the probability that Susan passes on the first try is 0.1275

d.

We'll make use of the probability of Susan passing the course after an infinite number of trials is 1.

i.e.

P(n=1) + P(n=2) + P(n=3) + P(n=4) + ......... = 1 --- This is then simplified to

P(n=1) + P(n=2) + P(n≥3) = 1

P(n≥3) = 1 - P(n=1) - P(n=2)

P(n≥3) = 1 - 0.85 - 0.1275

P(n≥3) = 0.0225

Therefore, the probability that Susan needs at least 3 attempts to pass is 0.0225

e.

In (a) above, we explained that the distribution is modeled by an exponential distribution.

The Expected Value for this is inverse of p, where p = 0.85

So, E(n) = 1/p

E(n) = 1/0.85

E(n) = 1.176470588235294

E(n) = 1.176 --- Approximated

Hence the Expected number of attempts is 1.176

7 0
4 years ago
Please help me! What is the simplest form for 21 /63 ?
creativ13 [48]

Answer:

1/3

Step-by-step explanation:


5 0
4 years ago
Please help I don’t understand number 16
Allisa [31]

Let's go step by step:

a) You are given four couples of x and y values which model the relationship between the number of drinks and their cost. So, the couple (x,y)=(0,0) means that if you buy zero drinks, you spend no money. That makes sense. The next information we have is (x,y) = (2,3), which means that two drinks cost 3 dollars, and so on.

So, you simply need to draw on the grid the four points

(0,0),\ (2,3),\ (4,6),\ (6,9)

b) The domain is the set of inputs. Since we only know the value of the function on four different points (we know the price for 0,2,4 and 6 drinks), the domain is discrete. In fact, a continuous domain must contain an interval (for example, [1,2] is a continuous domain), whereas if you pick a certain number of points (like in this case: we picked 0,2,4 and 6), the domain is discrete.

c) Once the points are drawn on the grid, you can see that they all lie on the same line. To find that line, we will only need two of those points (once two points are fixed, there is only one line passing through them). In general, the equation of the line passing through P = (P_x,P_y) and Q = (Q_x,Q_y) is

\cfrac{x-P_x}{Q_x-P_x} = \cfrac{y-P_y}{Q_y-P_y}

Let's choose, for example, the first two points. The equation is

\cfrac{x-0}{2-0} = \cfrac{y-0}{3-0} \iff \cfrac{x}{2} = \cfrac{y}{3} \iff y=\cfrac{3}{2}x

d) Now that we know the equation of the line, we can compute the cost of any number of drinks: the equation of the line is a function that associates a cost, y, with every possible number of drinks, x.

Of course, some associations will be odd - we can compute the cost of \sqrt{2} drink, but what would it mean?

Anyway, the question about the cost of two drinks seems more than reasonable, so let's see which y value is associate with the particular x value of 2:

y = \cfrac{3}{2} x \implies y = \cfrac{3}{2}\cdot 2 = 3

So, two drinks cost 3 dollars.

3 0
4 years ago
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