Ask question

Ask question

All categories

3 years ago

5

a driver is swimming 30 M below sea level. another Diver is taking a break on a platform that is 5 meters above sea level direct

ly above him. how far apart are the two divers

1 answer:

Thepotemich [5.8K]3 years ago

6 0

35 because the diver is 30 down and the other diver is 5 above land so it is going to be 35m between them.

You might be interested in

What is the area of a circle with a radius of 22 feet? Use \piπ= 3.14 and round your answer to the nearest tenth.

Alex17521 [72]

The correct answer 1519.8 feet^2

6 0

3 years ago

Read 2 more answers

PLEASE HELP<br><br> A<br><br> B<br><br> C<br><br> OR<br><br> D

iVinArrow [24]

Answer:

36 cm

Step-by-step explanation:

P = 2l + 2w

Plug in

P = 2(14) + 2 (4)

P = 28 + 8

P = 36

5 0

3 years ago

Read 2 more answers

Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2

nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

$12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0$

Now that we've factored our equation, we can use ZPP and break it up:

$2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}$

So, our solutions are:

$x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}$

4 0

3 years ago

Write a polynomial f (x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -4 (multiplicity 3), 1 (

yuradex [85]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -4 (multiplicity 3), 1 (multiplicity 1), and with f(0) = 320.

The first part zeros of -4 means (x+4) and multiplicity 3 means (x+4)^3.

The second part zeros of 1 means (x-1) and multiplicity 1 means (x-1).

The third part f(0) = 320 means substituting x=0 into (x+4)^3*(x-1)*k =320

(0+4)^3*(0-1)*k = 320

-64k = 320

k = -5

Combining all three conditions, f(x)

= -5(x+4)^3*(x-1)

= -5(x^3 + 3*4*x^2 + 3*4*4*x + 4^3)(x-1)

= -5(x^4 + 12x^3 + 48x^2 + 64x - x^3 - 12x^2 - 48x - 64)

= -5(x^4 + 11x^3 + 36x^2 + 16x -64)

= -5x^3 -55x^3 - 180x^2 - 80x + 320

8 0

3 years ago

Read 2 more answers

A function is shown f(x) = 2/3x +3 what is the value of f (6)?

Katena32 [7]

Answer:

The answer is 28/9

Step-by-step explanation:

Step one

Given information

We are given that the function is

$f(x) = 2/3x +3$

And we are expected to find f(6), that is substitute the value of x with 6

Step two:

$f(6)= 2/3(6)+3\\\\f(6)=2/18+3\\\\f(6)=1/9+3\\\\f(6)=1+27/9\\\\f(6)= 28/9$

5 0

3 years ago