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mojhsa [17]
3 years ago
10

Which sample is a pure substance

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer: container of zinc and oxygen

Hope this helps!

Explanation: edgenuity

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Show work please !!!!!!!!!
Alexxandr [17]
From the standards of the conversions of units:
1 in^3 = 0.01638 liters

To convert 320 in^3 into liters, we will simply use cross multiplication as follows:
displacement = (320 x 0.01638) / 1
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4 years ago
Milk (pH 6.7)
RoseWind [281]
Ammonia is the most basic and has the highest OH- concentration since it has the highest pH.
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3 years ago
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What is the energy of a photon using the given frequency and Planck's
nydimaria [60]

Answer:

Energy of photon is 34.45 ×10⁻¹⁹ J.

Explanation:

Given data:

Frequency of photon = 5.2×10¹⁵ s⁻¹

Plancks constant = 6.626×10⁻³⁴ Js

Energy of photon = ?

Solution:

Formula:

E = h.f

by putting values,

E =  6.626×10⁻³⁴ Js × 5.2×10¹⁵ s⁻¹

E = 34.45 ×10⁻¹⁹ J

Thus, energy of photon is 34.45 ×10⁻¹⁹ J.

8 0
3 years ago
What type of tissue is attached to the skeletal system and helps bones move f muscle tissue g cardiac tissue h adipose tissue j
MrMuchimi
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6 0
3 years ago
A 7.27-gram sample of a compound is dissolved in 250 grams of benzene. The freezing point of this solution is 1.02°C below that
almond37 [142]

Answer:

146 g/mol → option b.

Explanation:

This is a problem about the freezing point depression. The formula for this colligative property is:

ΔT = Kf . m . i

We assume i = 1, so our compound is not electrolytic.

ΔT = Freezing T° of pure solvent - Freezing T° of solution = 1.02 °C

m  = molality (mol of solute/kg of solvent)

We convert the grams of solvent (benzene) to kg → 250 g . 1 kg/1000 = 0.250 kg.

We replace → 1.02°C = 5.12°C/mol/kg . mol/ 0.250kg . 1

1.02°C / 5.12 mol/kg/°C = mol/ 0.250kg

0.19922 mol/kg = mol/ 0.250kg

mol = 0.19922 . 0.250kg → 0.0498 mol

molar mass = g/mol → 7.27 g / 0.0498mol = 146 g/mol

5 0
3 years ago
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