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Ket [755]
3 years ago
11

98,835 divided by 790 anybody? I keep getting this wrong...

Mathematics
1 answer:
stira [4]3 years ago
3 0
This was what I got.

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Use the counting techniques from the last chapter. A bag contains three red marbles, four green ones, one fluorescent pink one,
sergiy2304 [10]

Answer:

The probability that she gets all the red ones, given that she gets the fluorescent pink one, is P=0.0035 or 0.35%.

Step-by-step explanation:

Susan grabs four marbles at random.

We have to calculate the probabilities that he picks the 3 red ones, given that she already picked the fluorescent pink.

If it is given that the fluorescent pink is already picked, we are left with three red marbles, four green ones, two yellow ones, and four orange ones. A total of 13 marbles.

The probability that the second marble is red is 3 in 13.

The probability that the third marble is also red is 2 (the red marbles that are left) in 12 (the total amount of marbles left), as there is a picking without replacement.

The probability that the fourth marble is 1 in 11.

Then, the probability that the 3 red marbles are picked, is:

P=P_1\cdot P_2\cdot P_3=\dfrac{3}{13}\cdot \dfrac{2}{12}\cdot \dfrac{1}{11}=\dfrac{6}{1716}=0.0035

4 0
3 years ago
A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal
GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean income = \frac{\sum X}{n} = $4.70

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = $1.83

            n = sample of parking meters = 10

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.262 < t_9 < 2.262) = 0.95  {As the critical value of t at 9 degrees of

                                            freedom are -2.262 & 2.262 with P = 2.5%}  

P(-2.262 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.262) = 0.95

P( -2.262 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu < 2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.262 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.262 \times {\frac{s}{\sqrt{n} } } , \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 4.70-2.262 \times {\frac{1.83}{\sqrt{10} } } , 4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } } ]

                                         = [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error  =  2.262 \times {\frac{s}{\sqrt{n} } }

                                          =  2.262 \times {\frac{1.83}{\sqrt{10} } }  = <u>1.31</u>

4 0
3 years ago
Can someone please help me?? I'm begging...
wariber [46]

Answer:

What type of angle is it?

Step-by-step explanation:

5 0
3 years ago
There are 180 girls in a mixed school. lf the ratio of girls is to boys is 4:3 , the total number of students in the school is w
Angelina_Jolie [31]

Answer:

315

Step-by-step explanation:

No. of girls be g

No. of boys be b

g= 180

g/b = 4/3

b = 3g/4

b= 3(180/4)

b= 3*45

b= 135

.

Find b+g

= 135 + 180

= 315

3 0
3 years ago
What is the unknown fraction?
daser333 [38]

Answer:

A. 31/100

Step-by-step explanation:

Change 3/10 to hundreds:

3/10 × 10/10 = 30/100

The denominator (the bottom number) must be 100.

61 - 30 is 31.

The missing number is 31/100. See image.

4 0
2 years ago
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