Μ = (0×0.026) + (1×0.072) +(2×0.152) + (3×0.303) + (4×0.215) + (5×0.164) + (6×0.066)
μ = 0 + 0.072 + 0.304 + 0.909 + 0.86 + 0.82 + 0.396
μ = 3.361 ≈ 3.4
We need the value of ∑X² to work out the variance
∑X² = (0²×0.026) + (1²×0.072) + (2²×0.152) + (3²×0.303) + (4²×0.215) + (5²×0.164) + (6²×0.066)
∑X² = 0+0.072+0.608+2.727+3.44+4.1+2.376
∑X² = 13.323
Variance = ∑X² - μ²
Variance = 13.323 - (3.4)² = 1.763 ≈ 2
Standard Deviation = √Variance = √1.8 = 1.3416... ≈ 1.4
The correct answer related to the value of mean and standard deviation is the option D
<span>
An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.4 hours.</span>
2193 x 10(little 37) over 79
or
≈2.77595 x 10(little 38)
Answer:
Yes; James got 76 answers correct
Step-by-step explanation:
Round 1: 50 x 0.8 = 40
Round 2: 40 x 0.75 = 30
Round 3: 30 x 0.2 = 6
40 + 30 + 6 = 76
Answer:
42% i hope its right if not sorry
Step-by-step explanation:
Percent markup=amountmarkedup/original times 100
amountmarkedup=25-13.5.5=11.5
original=13.5
percent markup=11.5/13.5 times 100=0.85 times 100=85% markup
