Answer:
Between 150 and 200
Step-by-step explanation:
i just did the assignment .
1800 because the 18 cant fit in the tens
Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by

Where p is the population mean that is proportion of female students and n is the sample size.

Therefore, the standard deviation of the sampling distribution is 0.069.
Answer:
y=4x+6
Step-by-step explanation:
when x=0 y=6
when x=1 y=10
when x=2 y=14
to find y=50:
50=4x+6
44=4x
11=x
x=11 when y=50