Answer:
D) 26
Step-by-step explanation:
f(x) = 3x^2 - 6x + 2
Let x = -2
f(-2) = 3(-2)^2 - 6(-2) + 2
=3(4) +12+2
= 12 +12+2
=26
Answer:
x=5/2
Step-by-step explanation:
4x-2=2x+3
1) Add 2 to both sides:
4x=2x+5
2) Subtract 2x from both sides:
2x=5
3) Divide both sides by 2:
x=5/2
![(9\sin2x+9\cos2x)^2=81](https://tex.z-dn.net/?f=%289%5Csin2x%2B9%5Ccos2x%29%5E2%3D81)
Taking the square root of both sides gives two possible cases,
![9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1](https://tex.z-dn.net/?f=9%5Csin2x%2B9%5Ccos2x%3D9%5Cimplies%5Csin2x%2B%5Ccos2x%3D1)
or
![9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1](https://tex.z-dn.net/?f=9%5Csin2x%2B9%5Ccos2x%3D-9%5Cimplies%5Csin2x%2B%5Ccos2x%3D-1)
Recall that
![\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta](https://tex.z-dn.net/?f=%5Csin%28%5Calpha%5Cpm%5Cbeta%29%3D%5Csin%5Calpha%5Ccos%5Cbeta%5Cpm%5Ccos%5Calpha%5Csin%5Cbeta)
If
and
, we have
![\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}](https://tex.z-dn.net/?f=%5Csin%5Cleft%282x%2B%5Cdfrac%5Cpi4%5Cright%29%3D%5Cdfrac%7B%5Csin2x%2B%5Ccos2x%7D%7B%5Csqrt2%7D)
so in the equations above, we can write
![\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1](https://tex.z-dn.net/?f=%5Csin2x%2B%5Ccos2x%3D%5Csqrt2%5Csin%5Cleft%282x%2B%5Cdfrac%5Cpi4%5Cright%29%3D%5Cpm1)
Then in the first case,
![\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}](https://tex.z-dn.net/?f=%5Csqrt2%5Csin%5Cleft%282x%2B%5Cdfrac%5Cpi4%5Cright%29%3D1%5Cimplies%5Csin%5Cleft%282x%2B%5Cdfrac%5Cpi4%5Cright%29%3D%5Cdfrac1%7B%5Csqrt2%7D)
![\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi](https://tex.z-dn.net/?f=%5Cimplies2x%2B%5Cdfrac%5Cpi4%3D%5Cdfrac%5Cpi4%2B2n%5Cpi%5Ctext%7B%20or%20%7D%5Cdfrac%7B3%5Cpi%7D4%2B2n%5Cpi)
(where
is any integer)
![\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi](https://tex.z-dn.net/?f=%5Cimplies2x%3D2n%5Cpi%5Ctext%7B%20or%20%7D%5Cdfrac%5Cpi2%2B2n%5Cpi)
![\implies x=n\pi\text{ or }\dfrac\pi4+n\pi](https://tex.z-dn.net/?f=%5Cimplies%20x%3Dn%5Cpi%5Ctext%7B%20or%20%7D%5Cdfrac%5Cpi4%2Bn%5Cpi)
and in the second,
![\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}](https://tex.z-dn.net/?f=%5Csqrt2%5Csin%5Cleft%282x%2B%5Cdfrac%5Cpi4%5Cright%29%3D-1%5Cimplies%5Csin%5Cleft%282x%2B%5Cdfrac%5Cpi4%5Cright%29%3D-%5Cdfrac1%7B%5Csqrt2%7D)
![\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi](https://tex.z-dn.net/?f=%5Cimplies2x%2B%5Cdfrac%5Cpi4%3D-%5Cdfrac%5Cpi4%2B2n%5Cpi%5Ctext%7B%20or%20%7D-%5Cdfrac%7B3%5Cpi%7D4%2B2n%5Cpi)
![\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi](https://tex.z-dn.net/?f=%5Cimplies2x%3D-%5Cdfrac%5Cpi2%2B2n%5Cpi%5Ctext%7B%20or%20%7D-%5Cpi%2B2n%5Cpi)
![\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi](https://tex.z-dn.net/?f=%5Cimplies%20x%3D-%5Cdfrac%5Cpi4%2Bn%5Cpi%5Ctext%7B%20or%20%7D-%5Cdfrac%5Cpi2%2Bn%5Cpi)
Then the solutions that fall in the interval
are
![x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4](https://tex.z-dn.net/?f=x%3D0%2C%5Cdfrac%5Cpi4%2C%5Cdfrac%5Cpi2%2C%5Cdfrac%7B3%5Cpi%7D4%2C%5Cpi%2C%5Cdfrac%7B5%5Cpi%7D4%2C%5Cdfrac%7B3%5Cpi%7D2%2C%5Cdfrac%7B7%5Cpi%7D4)
So what do you need us to do for you?
Answer: I’m not for sure but I got 31,212
Step-by-step explanation: You multiply 30000 to 1.02 and then with the 2 and the 10 you divided and get 31,212