X²+35=0
X(x+35)=0
X=0 x+35=0
-35 -35
X=-35
x=0, x=-35
The formula in terms of h is h = 3V/s^2 and the value of h is 5
<h3>How to write the formula in terms of h?</h3>
The equation is given as
V = 1/3s^2h
Divide both sides of the equation by 1/3s^2
So, we have
h = 3V/s^2
The given parameters are
V = 60 and s = 6
So, we have:
h = 3 * 60/6^2
Evaluate
h = 5
Hence, the formula in terms of h is h = 3V/s^2 and the value of h is 5
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Answer:
The value of the house after adding the garage is $135,700.
Step-by-step explanation:
Given,
value of house before adding garage = $118,200.00
we need to find the value of house after adding two car garage.
Solution,
Since after adding two car garage the value of the house increased by 15%.
So firstly we will find out the 15% of the value of the house after adding garage.
So we can say that;
15% of the value of the house after adding garage is equal to 15 divided by 100 the multiplied with the value of the house before adding garage.
15% of the value of the house after adding garage = 
Now, The value of the house after adding garage is equal to the sum of value of house before adding garage and 15% of value of house before adding garage.
We can frame it in equation form as;
The value of the house after adding garage = 
Hence The value of the house after adding the garage is $135,700.