There is no choice on your list that must represent an odd integer.
If 'z' is an even integer, then (z-1) and (z+1) must both be odd integers.
The answer is B. It is a relation and also a function at the same time because it satisfies a specific domain
67 because 24 isnot 50 yet so you would keep 67 how it is but if it was 50 or more then you would round it up to 68
I’ll assume the c is b. (1/2) x (5) x (2) x (2) is 10
