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4 years ago

Is the ratio 12:14 written in simplest form? Yes No Practice Problems

Mathematics

1 answer:

zepelin [54]4 years ago

6 0

No you can make that into 6:7

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A sales person at a car dealership earns a monthly salary of $2400 and $250 for each vehicle sold

Mrrafil [7]

Step-by-step explanation:

8 vehicle.

Step-by-step explanation:

Given: Monthly salary of salesperson is $2400

Incentive of salesperson is $250 per vehicle sold.

First, lets compute income to earned apart from salary.

∴ Deduct salary from the target amount

\$ 4400-\$ 2400= \$ 2000$4400−$2400=$2000

∴ 2000 need to be earned only through incentive, which is2000needtobeearnedonlythroughincentive,whichis250 per vehicle sold.

Now, solving to get number vehicles to be sold to earn $2000 as incentive.

Number of vehicle= \frac{2000}{250}= 8\ vehicles2502000=8 vehicles

∴ 8 vehicles need to be sold by salesperson to get total earning as $4400

8 0

3 years ago

A cube is sliced as shown. Find the area of the cross section formed by the slice.

Alex

Answer:

Step-by-step explanation:

what you gotta do is multiply 5 * 7 to get 35

6 0

2 years ago

Read 2 more answers

The tangerine had 12 sections. I ate five sections. Dad ate 1/3. How much of the tangerine did we ate?

Kruka [31]

12-5=7 1/3 of 7=2.33333333

3 0

3 years ago

Stefan is measuring the angles of a triangle. He measures the first angle and gets a measure of 80° What does he know about the

zlopas [31]

The answer would be B, since the other two just have to equal 100.

6 0

4 years ago

Read 2 more answers

Find the differential of each function. (a) y = tan( 5t ) dy = Correct: Your answer is correct. (b) y = 5 − v2 5 + v2

Trava [24]

Answer:

$(a)$ $dy = 5sec^2(5t) \ dt$

$(a) \ dy = \frac{-20v}{(5+v^2)^2} \ dt$

Step-by-step explanation:

Given;

(a) y = tan(5t)

$(b) \ y = \frac{5-v^2}{5+v^2}$

Solving for (a)

y = tan(5t)

let u = 5t

⇒y = tan(u)

du/dt = 5

dy/du = sec²u

$\frac{dy}{dt} =\frac{dy}{du} *\frac{du}{dt} \\\\\frac{dy}{dt} = sec^2(u)*5\\\\\frac{dy}{dt} = 5sec^2(u)\\\\\frac{dy}{dt} = 5sec^2(5t)$

$dy = 5sec^2(5t) \ dt$

Solving for b;

let u = 5 - v²

du/dv = -2v

let v = 5+ v²

dv/du = 2v

$\frac{dy}{dv} = \frac{vdu - udv}{v^2} \\\\\frac{dy}{dv} = \frac{-2v(5+v^2) - 2v(5-v^2)}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-10v-2v^3-10v+2v^3}{(5+v^2)^2}\\\\$

$\frac{dy}{dv} = \frac{-10v-10v}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-20v}{(5+v^2)^2}\\\\dy = \frac{-20v}{(5+v^2)^2} dt$

4 0

3 years ago