2 years ago

Given g(x)=3x-3, solve for x when g(x)=6.

Mathematics

1 answer:

lana [24]2 years ago

7 0

Answer:

Step-by-step explanation:

g ( x ) = 6

g ( x ) = 3x - 3

3x - 3 = 6

3x = 6 + 3

3x = 9

x = 9 / 3

x = 3

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For $A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15$

Combine the fractions $\frac{2}{a} - \frac{5}{a} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{2-5}{a}$

$\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \ \frac{-3}{a}$

$\mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{b}=-\frac{a}{b} \ \textgreater \ -\frac{3}{a}$

Therefore our final answer is $A-\frac{3}{a}+\frac{1}{a^2}-8a+15$

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