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Nuetrik [128]
2 years ago
15

Which function is both continuous and differentiable for all x? I'm conflicted between A and D.

Mathematics
2 answers:
Vikki [24]2 years ago
8 0

Answer: A is the correct answer

Step-by-step explanation: D has a removable discontinuity at x =-3 and is not continuous.

damaskus [11]2 years ago
4 0

Answer:

A

Step-by-step explanation:

A is continuous:

x = 2

2³ = 8

4[3(2) - 4] = 8

D is undefined at x = -3

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I am having trouble with this problem ​
VladimirAG [237]

Answer:

12.566 sq inches

Step-by-step explanation:

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Through: (1,5), perp. to y=-1/10x + 3<br> pls help
Sedbober [7]
First to get the equation you knew to understand one thing about perpendicular lines. The slope of the line is the opposite reciprocal of the perpendicular lines or the new slope is m = 10.

Then you use the formula
y = mx + b
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8 0
3 years ago
Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in
Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces  of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

(50)^{2} = (14)^{2} + (48)^{2}

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm  lateral height = 35cm

(37)^{2} = (35)^{2}+ (6)^{2}

1369 = 1225 +36

1369 \neq 1261

Model 3

Diagonal = 60cm, radius = 20cm  lateral height = 40cm

(60)^{2} = (20)^{2} + (40)^{2}

3600 = 400 + 1600

3600 \neq 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

(30)^{2} = (24)^{2} + (9)^{2}

900 = 576 + 81

900 \neq 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion,  the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

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