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Rama09 [41]
3 years ago
9

Consecutive integers are 1,2,3,4 and so on. Consecutive even integers are 2,4,6,8 and so on. The sum of an integer and twice the

next consecutive even integer is 178. Write and solve an equation to find the two integeres. Let 2x represent the first even integer
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

the numbers are x=58 & x+2=60 , i.e. 58 and 60 .

<u>Step-by-step explanation:</u>

Here we have , Consecutive integers are 1,2,3,4 and so on. Consecutive even integers are 2,4,6,8 and so on. The sum of an integer and twice the next consecutive even integer is 178. We need to Write and solve an equation to find the two integers. Let's find out:

Let the integer be x  , and the next consecutive even integer be  x+2 .Now , According to question , The sum of an integer and twice the next consecutive even integer is 178 i.e.

⇒ x + 2(x+2)=178

⇒ x + 2x+4=178

⇒ 3x+4=178

⇒ 3x=174

⇒ \frac{3x}{3}=\frac{174}{3}

⇒ x=58

Therefore , the numbers are x=58 & x+2=60 , i.e. 58 and 60 .

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A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are
nikitadnepr [17]

Answer:

Area(A)=Area(C)= 9 in^{2}

Area(B)=13.2 in^{2}

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)=\frac{b*h}{2}=\frac{6*3}{2}=9 in^{2}

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

h=[tex]6*cos(30)=5.20in   The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

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3 0
3 years ago
The summit of a mountain pass is 8,050 ft above sea level. the valley below is 12 and 1/2 ft below sea level. what is the vertic
Veseljchak [2.6K]

Answer:

Vertical distance between the valley and the summit = 8062.5 ft

Step-by-step explanation:

Distances above the sea level are denoted by positive notations and below the sea level by negative notation.

Summit of a mountain pass = 8050 (above the sea level)

Valley below the sea level = 12 and half ft = (-12.5) ft

Distance between the summit and the valley = 8050 - (-12.5)

                                                                           = 8050 + 12.5

                                                                           = 8062.5 ft

Therefore, Vertical distance = 8062.5 ft will be the answer.

5 0
3 years ago
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