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3 years ago

What is twenty-five times five

Mathematics

1 answer:

OLga [1]3 years ago

6 0

Answer:

the answer is 125

Step-by-step explanation:

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a population of 55 foxes in a wildlife preserve triples every 11 years. the function y=55*3^x, where X is the number of 11-year

PolarNik [594]

Answer:

Step-by-step explanation:

7 0

3 years ago

Under her cell phone plan, Caroline pays a flat cost of $54.50 per month and $5 per gigabyte. She wants to keep her bill at $74

notsponge [240]

To stay within budget, she must use 3.9 gigabytes.

Giving the following information:

Under her cell phone plan, Sofia pays a flat cost of $54.50 per month and $5 per gigabyte. She wants to keep her bill at $ 74 per month.

First, we need to establish the total cost formula:

Total cost= 54.5 + 5*x

x= number of gigabytes

Now, we isolate x:

74= 54.5 + 5x

19.5/5= x

3.9= x

To stay within budget, she must use 3.9 gigabytes

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brainly.com/question/21316351

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3 0

1 year ago

Find the solution of the following system of equations -5+2y=9 3x+5y=7

Rudiy27

Answer:

$x=-\frac{28}{3}\\\\y=7$

Step-by-step explanation:

Given the system of equations:

$\left \{ {{-5+2y=9} \atop {3x+5y=7}} \right.$

You can pply Substitution method:

First you must solve for "y" from the first equation:

$-5+2y=9\\\\2y=9+5\\\\2y=14\\\\y=\frac{14}{2}\\\\y=7$

Therefore, the second and final step to solve the system of equations is to substitute the value of "y" into the second equation and solve for "x":

$3x+5(7)=7\\3x=7-35\\\\x=-\frac{28}{3}$

5 0

3 years ago

What is the volume of this right triangular prism 5cm 4.5 cm in 8 cm

Tresset [83]

The Volume Of The Right Triangular Prism Is 180 cm

8 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

3 years ago