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Taya2010 [7]
3 years ago
6

What is twenty-five times five

Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer:

the answer is 125

Step-by-step explanation:

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a population of 55 foxes in a wildlife preserve triples every 11 years. the function y=55*3^x, where X is the number of 11-year
PolarNik [594]

Answer:

Step-by-step explanation:

7 0
3 years ago
Under her cell phone plan, Caroline pays a flat cost of $54.50 per month and $5 per gigabyte. She wants to keep her bill at $74
notsponge [240]

To stay within budget, she must use 3.9 gigabytes.

Giving the following information:

Under her cell phone plan, Sofia pays a flat cost of $54.50 per month and $5 per gigabyte. She wants to keep her bill at $ 74 per month.

First, we need to establish the total cost formula:

Total cost= 54.5 + 5*x

x= number of gigabytes

Now, we isolate x:

74= 54.5 + 5x

19.5/5= x

3.9= x

To stay within budget, she must use 3.9 gigabytes

learn more of equation here

brainly.com/question/21316351

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3 0
1 year ago
Find the solution of the following system of equations -5+2y=9 3x+5y=7
Rudiy27

Answer:

x=-\frac{28}{3}\\\\y=7

Step-by-step explanation:

Given the system of equations:

\left \{ {{-5+2y=9} \atop {3x+5y=7}} \right.

You can pply Substitution method:

First you must solve for "y" from the first equation:

-5+2y=9\\\\2y=9+5\\\\2y=14\\\\y=\frac{14}{2}\\\\y=7

Therefore, the second and final step to solve the system of equations is to substitute the value of "y" into the second equation and solve for "x":

3x+5(7)=7\\3x=7-35\\\\x=-\frac{28}{3}

5 0
3 years ago
What is the volume of this right triangular prism 5cm 4.5 cm in 8 cm
Tresset [83]

The Volume Of The Right Triangular Prism Is 180 cm

8 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
3 years ago
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