Factor
(x+7)(x-2)
Proof
7-2=5
7*-2=-14
Zeros
x+7=0
x=-7
x-2=0
x=2
Final answer: C
The first one is true
<span>4(4a+10) is
</span>16 a + 40 after distribution
The second one is also true
<span>2(8a+20)
16a + 40 after distribution
Third is not true
</span><span>4a(4+10a)
</span><span>16a + 40a^2 after distribution
Last one is also true
</span><span>8(2a+5)
16a + 40 after distribution
Hope this helps :)</span>
Answer:
Step-by-step explanation:
Given:
m∠1 = 65°
Since. ∠1 and ∠2 are the angles of linear pair,
m∠1 + m∠2 = 180°
65° + m∠2 = 180°
m∠2 = 115°
m∠1 = m∠3 [Vertical angles]
m∠3 = 115°
Since, ∠1 and ∠4 is the linear pair of angles,
m∠1 + m∠4 = 180°
65° + m∠4 = 180°
m∠4 = 180 - 65 = 115°
m∠4 + m∠5 = 180° [Consecutive interior angles between the parallel lines]
115° + m∠5 = 180°
m∠5 = 180° - 115° = 65°
m∠5 + m∠6 = 180° [Linear pair of angles]
65° + m∠6 = 180°
m∠6 = 115°
m∠5 = m∠7 [Vertical angles]
m∠5 = m∠7 = 65°
m∠6 = m∠8 [Vertical angles]
m∠6 = m∠8 = 115°
