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malfutka [58]
3 years ago
7

A direct variation equation that relates x and y

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

Because X and Y vary directly, the equation is the form Y =KX. We can then solve for K by using the given values for X and Y. The equation that relates X and Y is Y= 5x

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
Mariulka [41]
678-9882

87299

Y s ukelele
4 0
3 years ago
In 1991, the moose population in a park was measured to be 1900. By 1997, the population was measured again to be 3600. If the p
LUCKY_DIMON [66]

Answer:

Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)

The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.

Step-by-step explanation:

.

8 0
3 years ago
Which equation can be used to find the perimeter of a regular octagon with sides of length 12?
USPshnik [31]
Octagans have 8 sides.
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There are 8 sides, each 12units in length.
Perimeter=8*12=96units
7 0
3 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
ASAP
poizon [28]
2x + 2(2x+3) = 360
2x +4x +6 = 360
6x  = 360 - 6
6x  = 354
x =  354/6
x = 59

answer: x = 59
5 0
4 years ago
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