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NARA [144]
3 years ago
14

Helen must find a certain polyhedron for a treasure hunt. use the clues to help helen identify the polyhedron.

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
The answer would be square pyramid
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Need a little bit of help
klemol [59]

Answer:

b

Step-by-step explanation:

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4 years ago
Find the value of x and the value of y.
stepladder [879]

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You haven't given enough information to answer the question.

Step-by-step explanation:

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3 years ago
Expand each expression
scoray [572]

Answer:

5log(a) +2log(b)

Step-by-step explanation:

you were close, but you dont multiply the exponents together since a and b are two different variables

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3 years ago
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What is a four digit whole number that is divisble by 2​
valentinak56 [21]

Answer:

any even number is divisible by 2.  

Here's an example:  2222

There are lots of others as well.

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4 years ago
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Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti
Vikki [24]

Answer:

General Solution is y=x^{3}+cx^{2} and the particular solution is  y=x^{3}-\frac{1}{2}x^{2}

Step-by-step explanation:

x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}

This is a linear diffrential equation of type

\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)..................(i)

here p(x)=\frac{-2}{x}

q(x)=x^{2}

The solution of equation i is given by

y\times e^{\int p(x)dx}=\int  e^{\int p(x)dx}\times q(x)dx

we have e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}

Thus the solution becomes

\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+cy=x^{3}+cx^{2

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have 6=8+4c

Thus solving for c we get c = -1/2

Thus particular solution becomes

y=x^{3}-\frac{1}{2}x^{2}

5 0
4 years ago
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