Are there choices? If there are, you should list them because there are some equivalents.
![\left[\begin{array}{cc}4&16\\12&3\end{array}\right] \\ \left[\begin{array}{cc}-68&16\\21&3\end{array}\right] = x \\ \left[\begin{array}{cc}4&-68\\12&21\end{array}\right] = y \\](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%2616%5C%5C12%263%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-68%2616%5C%5C21%263%5Cend%7Barray%7D%5Cright%5D%20%3D%20x%20%5C%5C%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-68%5C%5C12%2621%5Cend%7Barray%7D%5Cright%5D%20%3D%20y%20%5C%5C%20)
I'm assuming that you can solve these things. The top determinant comes to -180. The x value comes to - 540. When divided by the top one x = 3
The bottom determinant (y) comes to 900 and when divided by - 180 makes y = - 5. The checks out with actually solving the system of equations some other way.
Answer:
13$ dollars
Step-by-step explanation:
I hope this helps
F(x) = x^2 - 3x
f(-8) = (-8)^2 - 3(-8)
f(-8) = 16 - (-24)
f(-8) = 16 + 24
f(-8) = 40 (Answer)
Hope this helps
You reduce 24/36. 12/18, 6/9, 2/3
If you multiply the number of students times 8 you get 96, but if you multiply the students by 8 you need to multiply the adults by 8 as well. Which leaves you with 16 adults. Is there more to this equation? I feel like this is only part of it.