If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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The simplified expression is 6+3i
Answer:
An organism keeps growing because it's cells multiply. Cells are only meant to be a certain size yes but they're also meant to duplicate. For example cancer cells, they only grow so big but then they duplicate causing the tumor to grow bigger. Does that make sense?
Step-by-step explanation:
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Answer:
30
Step-by-step explanation:
We know that BD = 20 + 5 = 25. Let's call the point where BD and CE intersect point A. Therefore, ΔBAC ≅ ΔBAE by HL (BC = BE = 25 because they are radii, BA and AB are congruent because of the reflexive property). We can use Pythagorean Theorem to find CA. We can write CA² + 20² = 25² so CA = 15 and since CA = AE = 15 and CE = CA + CE, CE = 15 + 15 = 30.
Answer:
The probability is
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space
y-----> size of the sample space
so
In this problem we have
substitute