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WARRIOR [948]
3 years ago
13

Some researchers claim that herbal supplements (such as ginkgo biloba) can impact human memory. To test this claim, a researcher

selects a sample of n = 25 college students. Each student is given a ginkgo biloba supplement daily for six weeks and then all the participants are given a standardized memory test. For the population, scores on the test are normally distributed with µ = 70 with σ = 15. The sample of n = 25 students had a mean score of M = 76.a. Are the data sufficient to demonstrate that the herb has a significant effect on memory? Use a two-tailed test with
α
= 0.05.

b. Compute Cohen's d for this study.
Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

(a) The data are not sufficient to demonstrate that the herb has a significant effect on memory.

(b) Cohen's d = 5.07

Step-by-step explanation:

(a) Null hypothesis: The herbal supplement (ginkgo biloba) can impact human memory

Alternate hypothesis: The herbal supplement (ginkgo biloba) cannot impact human memory.

Z = (sample mean - population mean) ÷ sd/√n

Sample mean = 76, population mean = 70, sd = 15, n = 25

Z = (76 - 70) ÷ 15/√25 = 6 ÷ 3 = 2

Using a 0.05 significance level for a two tailed test, the critical value is 1.96

For a two tailed test, the region of no rejection of the null hypothesis lies between -1.96 and 1.96

Conclusion: Since the test statistic (Z = 2) falls outside the region bounded by -1.96 and 1.96, reject the null hypothesis. The herbal supplement (ginkgo biloba) cannot impact human memory.

Hence, the data are not sufficient to demonstrate that the herb has a significant effect on memory.

(b) Cohen's d = M/sd = 76/15 = 5.07

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Iris is a botanist who works for a garden that many tourists visit. the function f(s) = 2s + 25 represents the number of flowers
7nadin3 [17]

A function is said to be a composite function when a function is written in another function. The composite function that represents the number of flowers is f(w)=50w+25 and the number of flowers for 30 weeks is 1525.

Given that:

f(s)=2s+25

s(w)=25w

The number of flowers to bloom over w weeks is calculated using the following composite function: f(w)

f(s)=2s+25

Replace s with s(w)

f(s(w))=2(s(w))+25

Substitute (w)=25w

f(s(w))=2(25w)+25

f(s(w))=50w+25

Hence:

f(w)=50w+25

The units of the measurement of f(w) are flowers

The number of flowers for 30 weeks means:

w=30

So, we have:

f(w)=50w+25

f(30)=50 * 30+25

f(30)=1525

Hence, the number of flowers for 30 weeks is 1525

Learn more about composite functions here:brainly.com/question/10687170

#SPJ4

5 0
2 years ago
From 12,000 graphing calculators produced by a​ manufacturer, an inspector selects a random sample of 550 calculators and finds
maria [59]

Answer:

131

Step-by-step explanation:

Using proportion,

If Out of 550 calculators = 6 are defective,

Then out of 12000 calculators = ? are defective

\frac{12000 calculators}{550calculators} * 6

= 21.8 * 6

= 130.8 ≈ 131

∴ Approximately 131 calculators are defective

3 0
3 years ago
The temperature at the south pole was 6 degrees at 8am. At 3 pm it was -18 degrees. By how many degrees did the temperature drop
olga2289 [7]

Answer:

24\°

Step-by-step explanation:

we know that

To determine how many degrees drop the temperature, find out the absolute value of subtract the temperature at 8 am from the temperature at 3 pm.

so

\left|-18-6\right|=24\°

7 0
3 years ago
Find the value of x.
GaryK [48]

Answer:

x = 25

Step-by-step explanation:

it's an isosceles triangle so base angles are the same

3x - 30 = 45

Add 30 on both sides

3x = 75

divide both sides by 3

x = 25

5 0
3 years ago
Determine the length of the leg of a 45o – 45o – 90o triangle with a hypotenuse length of 15 inches. ( ANSWER NEEDS TO BE IN RED
SIZIF [17.4K]

Answer:

The lenghts of both legs: \frac{15\sqrt{2}}{2}\ inches

Step-by-step explanation:

By definition, when a triangle has angles that measures 45°, 45° and 90°, its legs are congruent.

Then, knowing the lenght of the hypotenuse, we can find the lenght (in inches) of  any leg of the given triangle by applying the Trigonometric Identity sin\alpha=\frac{opposite}{hypotenuse}:

sin(45\°)=\frac{leg}{15}\\\\leg=\frac{15}{\sqrt{2}}

Finally, simplifying, we get:

leg=\frac{15(\sqrt{2})}{(\sqrt{2})(\sqrt{2})}=\frac{15\sqrt{2}}{2}

3 0
3 years ago
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