Answer:
<h2>The demand at a price of $1.50 per cone is 44 cones</h2>
Step-by-step explanation:
let us apply the interpolation formula to solve this problem
we have
Now let us set the values to the notation above
x= $1.20
x1= $2.20
x2= $1.50
y = 50 cones
y1= 30 cones
y2= ?
Substituting our given data we have
the demand at a price of $1.50 per cone is 44 cones
The starting percent is 100%. After one hour, bacteria tripled, so it is 300%.
D : c = 33 : 22
where d is the number of dogs and c is the number of cats;
and: d + c = 3030
33 c = 22 d / : 11
3 c = 2 d
From the other equation: c = 3030 - d
3 * ( 3030 - d ) = 2 d
9090 - 3 d = 2 d
5 d = 9090
d = 9090 : 5
d = 1818
Answer: There are 1818 dogs in the shelter.
a^2 - b^2 = (a + b)(a - b)
In this case
49x^4y^2 - 4z^2
= (7x^2y)^2 - (2z)^2
= (7x^2y + 2z)(7x^2y - 2z)
Factors are (7x^2y + 2z) and (7x^2y - 2z)
Answer:
D) 7x^2y + 2z
Answer:
I believe the correct answer is $10,000. I'm not positive, though.
