What is the policy about blank assignments, essays, or short answer questions?

foreshadowing: what elements of the description of the caverns contribute to the mood of approaching danger?

Lelu [443]

Foreshadowing is the literary technique that is used to make predictions about the events that would still occur in a work of fiction by making use of hints.

As a result of this, an author can make use of some elements such as:

Dialogue
Motifs
Symbols
Metaphor, etc

Please note that your question is incomplete and therefore i am giving you a general overview that should help you arrive at the right answer.

Mood is the general feeling that a reader gets when reading a literary piece.

As a result of this, an author can make use of descriptive words to show the mood of an impending danger. Some sentences that can display this are:

"Remember the terrible event that occured two years ago? It could happen again!"
"I don't want my daughter to find out I am not her real father as she could run away!"

Read more about sample space at:

brainly.com/question/2117233

7 0

1 year ago

Which part of your body is affected by poor ergonomics??

saveliy_v [14]

Pain in the fingers, wrists, or other parts of the body: may include a dull aching pain, a sharp stabbing pain, or even a burning sensation

5 0

3 years ago

Which of the following patterns does not affect Law of Demand?

Angelina_Jolie [31]

I believe the answer is D) none of these patterns effect

5 0

3 years ago

suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a

saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

 I hope this is understandable and if my answer helped you please can you give me a brainliest its will really help me and thank you have a nice day!!

3 0

2 years ago

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