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3 years ago

13

Given the original number n. Multiply the number by 9. Add 99. Divide this sum by 9. Subtract the original number, n, from the q

uotient.

1 answer:

tangare [24]3 years ago

4 0

Answer:

11

Step-by-step explanation:

Hello,

Given the original number n.

$\large \boxed{n}$

Multiply the number by 9.

$\large \boxed{9n}$

Add 99.

$\large \boxed{9n+99}$

Divide this sum by 9.

$\large \boxed{\dfrac{9n+99}{9}=n+11}$

Subtract the original number, n, from the quotient.

$\large \boxed{n+11-n=11}$

Thank you.

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During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem

liraira [26]

Answer:

3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

$\text{The amount of sold apples during 1st hour}=\frac{15}{100}x=0.15x$

$\text{The amount of remaining apples after 1st hour}=x-0.15x$

$\text{The amount of remaining apples after 1st hour}=0.85x$

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

$\text{The amount of sold apples during 2nd hour}=0.85x*\frac{20}{100}$

$\text{The amount of sold apples during 2nd hour}=0.85x\times 0.20$

$\text{The amount of sold apples during 2nd hour}=0.17x$

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

$25.5=0.17x$

$\frac{25.5}{0.17}=\frac{0.17x}{0.17}$

$150=x$

So, stand owner had initially 150 kg of apples.

$\text{The amount of remaining apples after 2nd hour}=0.85x-0.17x$

$\text{The amount of remaining apples after 2nd hour}=0.68x$

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

$\text{The amount of sold apples during 3rd hour}=0.68x*\frac{25}{100}$

$\text{The amount of sold apples during 3rd hour}=0.68x*0.25$

$\text{The amount of sold apples during 3rd hour}=0.17x$

$\text{The amount of remaining apples after 3rd hour}=0.68x-0.17x$

$\text{The amount of remaining apples after 3rd hour}=0.51x$

As remaining apples were sold 5% more each following hour.

$\text{The amount of sold apples during 4th hour}=0.51x*\frac{5}{100}$

$\text{The amount of sold apples during 4th hour}=0.51x*0.05$

$\text{The amount of sold apples during 4th hour}=0.0255x$

Let us substitute x=150 into above equation we will get,

$\text{The amount of sold apples during 4th hour}=0.0255*150$

$\text{The amount of sold apples during 4th hour}=3.825$

Therefore, 3.825 kg of apples were sold during the 4th hour.

7 0

3 years ago

What is the length ?

Brums [2.3K]

Answer:

AC = 2x - 13 Cm

BC = 3x + 4 Cm

AB = 36 Cm

AB = AC + BC

BC = AB - AC

= 36 - (2x - 13)

= 36 - 2x + 13

= 49 - 2x

but, BC = 3x + 4

so equating both the equation we get

3x + 4 = 49 - 2x

3x + 2x = 49 + 4

5x = 53

x = 53/5

x = 10.6

BC = 49- 10.6*2

= 49- 21.2

= 27.8 CM

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Which decimal is equivalent to 8%

Nikitich [7]

Answer:

$0.08$

Step-by-step explanation:

Given : 8%

To find the decimal value of the percentage number

Remove the percentage symbol with 100 in the denominator

gives

$\frac{8}{100}\\$

Now taking the numerator to the decimal place equal to the number of zeros in the denominator or simply divide denominator with numerator.

Gives = $0.08$

So, the decimal equivalent of the given value is $0.08$

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Simplify (sec θ – tan θ)2

rusak2 [61]

Answer:

2 sec (θ ) − 2 tan ( θ )

Step-by-step explanation:

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