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sergey [27]
1 year ago
11

Describe the accumulated value a of the sum of money P the principal after two years at annual percent rich are in the decimal f

orm compounded continuously complete the table for the saving account subject to continuous compounding.

Mathematics
1 answer:
elena-14-01-66 [18.8K]1 year ago
8 0

In order to calculate the value of t, we can use the given formula with the values P = 6000, A = 2P and i = 11% = 0.11:

\begin{gathered} 2\cdot6000=6000\cdot e^{0.11t}\\ \\ 2=e^{0.11t}\\ \\ \ln2=\ln e^{0.11t}\\ \\ 0.693147=0.11t\\ \\ t=\frac{0.693147}{0.11}=6.3 \end{gathered}

Therefore the time needed is t = 6.3 years.

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Answer:

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Step-by-step explanation:

6 0
3 years ago
5#The distribution of scores on a standardized aptitude test is approximately normal with a mean of 480 and a standard deviation
kirza4 [7]

We want to find the value that makes

P(X\ge x)=0.2

To find it we must look at the standard normal table, using the complementary cumulative table we find that

P(Z\ge z)=0.20045\Leftrightarrow z=0.84

Then, using the z-score we can find the minimum score needed, remember that

z=\frac{x-\mu}{\sigma}

Where

σ = standard deviation

μ = mean

And in our example, x = minimum score needed, therefore

\begin{gathered} 0.84=\frac{x-480}{105} \\  \\ x=0.84\cdot105+480 \\  \\ x=568.2 \end{gathered}

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.

7 0
1 year ago
If $1800 is invested at a rate of 1.4% compounded continuously find the number of years it will take for the balance to reach $2
Ede4ka [16]

Answer:4

Step-by-step explanation:

8 0
3 years ago
The weights of a certain dog breed are approximately normally distributed with a mean of μ = 55 pounds, and a standard deviation
weqwewe [10]

Answer:

(a)z=-1

(b)48.5 pounds

(c)61.5 pounds

Step-by-step explanation:

z-score=\dfrac{x-\mu}{\sigma}

Given:

Mean, μ = 55 pounds

Standard deviation,σ = 6 pounds.

(a)For a dog that weighs 49 pounds.

x=49 pounds

The z-score

=\dfrac{49-55}{6}\\=\dfrac{-6}{6}\\\\=-1

(b)When a dog has a z-score of -1.09

-1.09=\dfrac{x-55}{6}\\x-55=-6.54\\x=55-6.54\\x=48.46 \approx 48.5$ pounds (to the nearest tenth)

The weight of a dog with a z-score of -1.09 is 48.5 pounds.

(c)When a dog has a z-score of 1.09

1.09=\dfrac{x-55}{6}\\x-55=6.54\\x=55+6.54\\x=61.54 \approx 61.5$ pounds (to the nearest tenth)

The weight of a dog with a z-score of 1.09 is 61.5 pounds.

3 0
3 years ago
Need help with ratios quick plss
dalvyx [7]
X/3=y this is what I got hopes this helps
3 0
2 years ago
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