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3 years ago

A line has a slope of -1/3 and includes the points (q, 2) and (6, 3). What is the value of q?

Mathematics

1 answer:

elena55 [62]3 years ago

3 0

Answer:

Step-by-step explanation:

Given the knowledge that the slope is -1/3 and includes the point (6,3), you can subtract one from the y value and add three to the x value, resulting in (9,2). Q is equal to 9.

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Please answer this question!! 30 points and brainliest!

murzikaleks [220]

Answer:

D. 2x^2-7x.

Step-by-step explanation:

Lets write it out to make it easy to work with.

-x(-2x+7)

Multiply the -x out

2x^2-7x.

The answer is D

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3 years ago

How much interest will he earn? A) $120 B) $60 C) $50 D) $600

zubka84 [21]

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3 years ago

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Please help i will give crowns

jeka57 [31]

Answer:

1/24

Step-by-step explanation:

(1/6) divided by 4

(1/6)/4

is the same as

1/(6*4) = 1/24

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2 years ago

Please help fast i will give you the most Brainly what would n = 3(n+7)=48

neonofarm [45]

Answer:

n = 9

Step-by-step explanation:

3(n+7)=48

distribute

3n +21 = 48

subtract 21 from each side

3n = 48-21

3n = 27

divide by 3

3n/3 = 27/3

n = 9

5 0

3 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

3 years ago