Question

Second last question what is the area of this compound shape?​

Answer 1

Answer:

43.12 yd²

Step-by-step explanation:

Semicircle + triangle

½×pi×r² + ½×b×h

½(3.14)(4²) + ½(4)(9)

43.12 yd²

Answer 2

Answer:

43.13 yd squared

Step-by-step explanation:

This is a figure composed of a semicircle and a right triangle.

Triangle:

The area of a triangle is denoted by A = (1/2) * B * h, where b is the base and h is the height. Here, the base is actually also the radius of the semicircle, which is 4. The height is 9. Plug these in: A = (1/2) * 4 * 9 = 36/2 = 18 yd squared.

Semicircle:

The area of a semicircle is denoted by A = $(1/2)\pi r^{2}$, where r is the radius. Here the radius is 4. So: A = $(1/2)\pi *4^{2}=8\pi$ ≈ 25.13 yd squared.

Adding these up: 18 + 25.13 = 43.13 yd squared

Hope this helps!