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faust18 [17]
3 years ago
10

93748 x 837482768836334

Mathematics
2 answers:
AlexFokin [52]3 years ago
3 0
42 to the power of 100
Ahat [919]3 years ago
3 0

Answer:

7.8512335e+19

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9 = 40 + 13<br> Helpppppp I need it due today
patriot [66]

Its is equal to 9x6=53 Goodluck

7 0
3 years ago
What is 2/7 and 4/28 with a common denominator
LekaFEV [45]
2/7 could be 8/28 giving you a common denominator.  Or you could have 4/14 and 2/14.
7 0
4 years ago
Read 2 more answers
An artist is using tiles and boards for a project. A tile has length 1/3 ft and width 1/3 ft. A board has length 1/4yd and width
Nezavi [6.7K]

We have been given that

The length of the tile is given by 1/3 feet.

The width of the tile is given by 1/3 feet.

The length of the board is given by 1/4 yd.

The width of the board is given by 1/4 yd.

We know that 1 feet = 0.33 yard

Hence, we have

The length of the tile =  \frac{1}{3} \cdot 0.33= 0.11 yd

The width of the tile =  \frac{1}{3} \cdot 0.33= 0.11 yd

Hence, the ratio of length of the tile to the length of the​ board is given by

\frac{0.11}{1/4} \\&#10;\\&#10;\frac{44}{100} \\&#10;\\&#10;\frac{11}{25} \\

Area of tile = 0.11 \times 0.11 = 0.0121 square yd.

Area of board is \frac{1}{4} \times \frac{1}{4} = \frac{1}{16}

Therefore, the ratio of the area of the tile to the area of the​ board is given by

\frac{0.0121}{1/16} \\&#10;\\&#10;\frac{121}{625}

6 0
3 years ago
The heights of male are normally distributed with mean of 170 cm and standard deviation
Bumek [7]

Answer:

0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 170cm and standard deviation of 7.5 cm.

This means that \mu = 170, \sigma = 7.5

Find the probability that a randomly selected male has a height > 180 cm.

This is 1 subtracted by the pvalue of Z when X = 180. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{180 - 170}{7.5}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

1 - 0.9082 = 0.0918

0.0918 = 9.18% probability that a randomly selected male has a height > 180 cm.

4 0
3 years ago
Find the 95th term of the arithmetic sequence 4,-5,-14
mestny [16]

Answer:

Step-by-step explanation:

d = - 9

a = 4

n = 95

tn = a + (n - 1)*d

t95 = 4 + (94)*(-9)

t95 = 4 -846

t95 = - 842

7 0
3 years ago
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