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Ksenya-84 [330]
2 years ago
14

P3. (3+5 points) Let k be any natural number. (a) Prove that for every positive integer n, we have σk(n) = σ−k(n)n k . Conclude

that n is a perfect number exactly when σ−1(n) = 2. (b) Prove that for all positive integers n, we have σ1(n) ≤ n log(n + 1) + γn, where γ is Euler’s constant defined in class. (In this course, log x = loge x denotes the natural logarithm). g
Mathematics
1 answer:
Mrac [35]2 years ago
8 0

Answer:

what????????????

Step-by-step explanation:

what is this my guy

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I don't know how to do things like this :(​
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the rectangle below is shown with dimensions in inches the rectangle is tiled using squares that are 1/8 in each edge what is th
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3 years ago
Convert 7/11 to a percent. round the answer to the nearest hundredth
pychu [463]
<h3>Answer:</h3>

63.64%

<h3>Step-by-step explanation:</h3>

7/11 = 7/11 × 100% = (700/11)% ≈ 63.64%

_____

<em>Comment on fractions involving 11</em>

1/11 is the 2-digit repeating decimal 0.09090909...

So, any multiple of 1/11 is a 2-digit repeating decimal with the two digits being the numerator times 9.

Here, we have 7/11, so the 2-digit repeat is 7·9 = 63. That is ...

... 7/11 = 0.63636363...

3 0
3 years ago
Please help!<br><br> If sin(xº)=cos(yº) find k if x=2k+3 and y=6k+7
USPshnik [31]

answer

10

step-by-step explanation

the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7

substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)

sin(x) = cos(y)

sin(2k + 3) = cos(6k + 7)

we know that sin(x) = cos(90 -x)

sin(2k + 3)

= cos(90 - (2k + 3) )

= cos(90 - 2k - 3)

= cos(87 - 2k)

substitute this into the equation sin(2k + 3) = cos(6k + 7)

sin(2k + 3) = cos(6k + 7)

cos(87 - 2k) = cos(6k + 7)

87 - 2k = 6k +7

80 = 8k

k = 10

7 0
3 years ago
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