The vertex form of the equation of a parabole is (x - h)^2 + k
So you must complete squares to transform x^2 -2x - 6 in its vertex form.
1) convert x^2 - 2x in a square => (x - 1)^2 - 1
2) Add the constant term - 6 => (x - 1)^2 -1 - 6
3) Add similar terms => (x - 1)^2 - 7
You can verify that (x - 1)^2 - 7 is equal to x^2 - 2x - 6:
x^2 - 2x + 1 - 7 = x^2 - 2x - 6. So, do not doubt it, the vertex form is (x - 1)^2 - 7, where the coordinates of the vertex are (1, - 7)
Answer: option A (x - 1)^2 - 7
= v/t
= 13-7/2
= 6/2
<span>= 3 m/sec² </span>
Well.... exterior means "on the outside", so whichever triangle does not have angle 2 on the outside, I guess.
S = 32 and t = 45
You replace the letters into numbers...
Since (st) is the same thing as (s × t), it would be 32 × 45, which equals to 1,440.
Then replace the r with 5, so now it's (6 × 5), instead of (6r).
st ÷ (6r) → 1,440 ÷ 30 = 48
Value of st ÷ (6r) = 48
Answer:
Step-by-step explanation:
<u>Step 1 :</u>-
<u>Perpendicular condition :-</u>
<u>Step 1:-</u>
Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.
<u>Step 2:-</u>
The given points are (-8,k) and (-4,-8)
finding slope of the first line is
using formula
=
finding slope of the second line is
using formula
=
<u>Step 3:</u>-
using perpendicular condition
The two lines are perpendicular and their slopes are
simplification,we get solution is
<u>Final answer is </u>