Gluconeogenesis occurs in the liver due to the action of

fenix001 [56]

Climate Changes with Latitude. Places located at high latitudes (far from the equator) receive less sunlight than places at low latitudes (close to the equator). The amount of sunlight and the amount of precipitation affects the types of plants and animals that can live in a place

6 0

2 years ago

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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

Agata [3.3K]

Answer:

2,855 is the size of the colony of mosquitoes after 4 days.

Explanation:

The law of uninhibited growth is given as:

$A=A_o\times e^{k\times t}$

$A_o$ = Original amount

A = Amount after time t

k = Positive constant repressing the rate of growth

We are given with:

Original population of mosquitoes = 1000

Population of mosquitoes after 1 day =1300

t = 1 day

$1300=1000\times e^{k\times 1 day}$

$k = 0.2623 day^{-1}$

Population size of mosquitoes after 4 days

$A_o=1000, k= 0.2623 day^{-1}$

A =? , t = 4 days

$A=1000\times e^{ 0.2623 day^{-1}\times 4 days}$

A =2,855.36 ≈ 2,855 mosquitoes

2,855 is the size of the colony of mosquitoes after 4 days.

5 0

3 years ago

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Cells that have differentiated still have most of their genes and they

Irina18 [472]

Still create mor which is called celluar respiration

7 0

2 years ago

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Which type of growth can occur only when a population has unlimited resources?

tigry1 [53]

C. Exponential growth occurs when there is unlimited resources. Since there is a surplus of food, there are a lot more babies are born because of the favorable circumstances.

Hope this helps :)

6 0

2 years ago

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A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by

bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that the probability that, given enough time, all tigers in the population will have horizontal stripes is 30% = 0.3.

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Available data:

Population size, N = 100 tigers
Number of Tigers with horizontal stripes = 30
Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

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You can learn more about Hardy-Weinberg equilibrium at

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6 0

2 years ago