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aleksandrvk [35]
3 years ago
13

Solve the equation 2/5x-1=9. Complete each step of the solution and check your solution

Mathematics
1 answer:
Fofino [41]3 years ago
3 0

Answer:

x = 25

Step-by-step explanation:

2/5x - 1 = 9

Add 1 to both sides

2/5x = 10

Multiply by 5 on both sides

2x = 50

Divide by 2 on both sides

x = 25

Check the answer:

Plug in 25 for x

2/5(25) - 1 = 9

10 - 1 = 9

9 = 9

The answer is correct.

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Step-by-step explanation:

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2 years ago
Simplify. 6m+7n+5m−3nhow to earn points
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Answer:

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3 years ago
Hurry 50 points for correct answer
Ad libitum [116K]

Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

Step-by-step explanation:

The equation x=\sqrt{6x+7} can be solved by squaring both sides:

x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

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The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

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3 years ago
Biologists were studying the proportions of cats that had spotted markings on their fur in two populations of cats, C and F. An
alexandr1967 [171]

Answer:

If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01.

Step-by-step explanation:

p-value is the probability of observing a result which is at least as extreme as we calculated in our actual workings, assuming the Null hypothesis to be true.

The calculate p-value is 0.01. In the question statement we are given that the alternate hypothesis is:

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Since, Null and Alternate Hypothesis are negations of each other, the Null Hypothesis would be:

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We assume the null hypothesis to be true, perform the tests on the sample and obtain a result.

The results we obtained is:

The sample difference is 0.62

Fitting all this data, in the definition of p value tell us that:

The probability of obtaining a sample difference of atleast 0.62 is 0.01, if the population proportions are same.

This matches with the option B. Therefore, the correct answer is:

If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01.

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