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sergeinik [125]
3 years ago
9

Which of the following statement is NOT a reasonable statement about geometry?

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

D. You need to take geometry so you will learn how to drive farther and faster.

Step-by-step explanation:

Geometry can help you earn credit and teach you real-world skills that can even be applied to a future career of your choice!

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32=32+? I need help its annoyings
Andreyy89

Answer:

0

Step-by-step explanation:

32=32+0

5 0
3 years ago
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Match them!
ASHA 777 [7]

Answer: a - 4

b - 1

c - 2

d - 3

e - 5

Step-by-step explanation:

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3 years ago
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Consider two circular swimming pools. Pool A has a radius of 22 feet, and Pool B has a diameter of 13.6 meters. Complete the des
maw [93]

Answers:

13 42 m; B; 0.57 m

Step-by-step explanation:

Data:

Pool A:  r = 22 ft

Pool B: D = 13.6 m  

Calculations:

1. Radius of Pool A

r = 22 ft × (0.305 m/1 ft) = 6.71 m

2. Diameter of Pool A

D =2r = 2 × 6.71 = 13.42 m

The diameter of Pool A is 13.42 m.

3. Compare pool diameters

The diameter of Pool B is 13.6 m.

So, the diameter of Pool <u>B</u> is greater.

4. Compare circumferences

The formula for the circumference of a circle is

C = 2πr or C = πD

Pool A: C = 2π × 6.71 = 42.16 m

Pool B: r =    π × 13.6 = 42.73 m

Pool B - Pool A = 42.73 - 42.16 = <u>0.57 m </u>

The circumference is greater by <u>0.57 m.</u>

8 0
3 years ago
Which statement below is an example of the
Hitman42 [59]

Answer:

B

Step-by-step explanation:

Let say, a=9,b=11,c=6

Then associative properties says that every element is related to each other, here "b" associates a &c.

Therefore, a is related to b+c

c is related to a+b

3 0
3 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
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