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GrogVix [38]
3 years ago
13

Pointssss

Mathematics
1 answer:
lozanna [386]3 years ago
7 0

Answer:

This might be the answer not sure

Step-by-step explanation:

if it goes down 0.8 % every year it would be 1392

this is what I did 1,450−0.8%−0.8%−0.8%−0.8%

−0.8% I did -0.8% for every year i did 5 times for 5 years

so that the value but if u want the really accurate one then the answer is 1,392.9206056485 i hate myself for doing that but yeah thats it

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Mashcka [7]
It’s not 3 or 4 so I think 2
7 0
3 years ago
What are the correct answers?
Delvig [45]
1. y= -x - 15
2. y= -4x + 1/2
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4. y= 2/3x + 3
5. y= -1/2x - 4
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Glad I could help
8 0
2 years ago
Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C
Zarrin [17]

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

A(5.3) = 0.5A(0)

We use this to find r. So

A(t) = A(0)(1-r)^t

0.5A(0) = A(0)(1-r)^{5.3}

(1-r)^{5.3} = 0.5

\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}

1 - r = 0.5^{\frac{1}{5.3}}

1 - r = 0.8774

So

A(t) = A(0)(0.8774)^{t}

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that A(26.5) = 14.5, and use this to find A(0). So

A(t) = A(0)(0.8774)^{t}

14.5 = A(0)(0.8774)^{26.5}

A(0) = \frac{14.5}{(0.8774)^{26.5}}

[tex]A(0) = 464[tex]

464 grams.

3 0
3 years ago
If f:X is 3x + b and ff(2) = 12, find the value of b​
Tamiku [17]

Answer:

b =6

Step-by-step explanation:

Given

f(x) =3x + b

f(2) = 12

Required

Find b

f(2) = 12 implies that:

12 = 3 * 2 + b

12 = 6 + b

Collect like terms

b = 12 - 6

b =6

5 0
3 years ago
PLZ HELP!!!!!!! NO LINKS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Studentka2010 [4]

Answer:

i can't see clear

4 0
2 years ago
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