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Vika [28.1K]
4 years ago
13

(4, 3) is a solution to the following system of equations:

Mathematics
1 answer:
sasho [114]4 years ago
4 0
The first answer is true and the second answer is true as for how this actually is just plug in the numbers

x=4, y=3

2(4)=8 8+3=11

4-1=3
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haley puts these 12 tiles in a bag and shakes the bag.Then she picks a tile at random.What is the probability she picks a tile t
kirill [66]

Answer:

1 in 3 chance

Step-by-step explanation:

Multiples of 3: 3, 6, 9, 12

This means there are 4 multiples.

4/12 or 4 ÷ 12 = 1/3

So there is a 1 in 3 chance (33.333%) to get a multiple of 3

6 0
3 years ago
Helppppp needed plz quick
olga nikolaevna [1]

Answer:

Step-by-step explanation:

9x - 77 = 7x - 43

2x - 77 = -43

2x = 34

x = 17

9(17) - 77 = 153 - 77 = 76

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3 years ago
Find the value of y in the diagram below
elena55 [62]

we \: can \: tell \: that \\ 1. \:  \: 13x - 26 = 7x + 16 \\ 2. \:  \: 7 x + 16  + 9y + 7  = 180\\ from \: 1. \\ 6x = 42 \: so \: x = 7 \\ from \: 2. \\ y = 12
3 0
3 years ago
Read 2 more answers
Is BA(OH)2 soluble or insoluble in water
andreev551 [17]

Answer: soluble

Step-by-step explanation:

4 0
3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
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