All categories

4 years ago

Find the sum of the first 5 terms of the sequence 4,2,0

Mathematics

2 answers:

lora16 [44]4 years ago

7 0

Answer:

27/4=6 3/4

Step-by-step explanation:

2^2,2^1,2^0 so the next will be 2^(-1),2^(-2)

the sum will be 4+2+0+1/2+1/4=16/4+8/4+2/4+1/4=27/4

Free_Kalibri [48]4 years ago

6 0

4,2,0,-2,-4,-6,-8,-10 because you subtract 2 each time

You might be interested in

What is the effective rate of a $30,000 non-interest-bearing simple discount 5%, 60-day note?

balu736 [363]

30000 due at the end of 60 years
I'll assume that the number of days in year is 360
I=30,000×0.05×(60÷360)=250

Cash in hand at the beginning of 60 days is
30,000−250=29,750

The effective rate is
R=I÷pt
R=250÷(29,750×(60÷360))
R=0.0504×100
R=5.04%

5 0

3 years ago

Read 2 more answers

The coordinates of the vertices of a quadrilateral ABCD are A(-5, 8), B(-2, 9) C(3, 4) and D(0, 3). Determine if ABCD is a parel

Setler79 [48]

Answer:

It is a parellelogram

Step-by-step explanation:

;)

4 0

3 years ago

What is the shape of the graph of the function?<br> h(x) =2.05*3^x

myrzilka [38]

Answer: A

Step-by-step explanation:

6 0

3 years ago

Simplify the expression.

stealth61 [152]

Answer:

(D)

Step-by-step explanation:

The power 3 going to the numerator and denominator.

So the answer is 27x3/y3. (D)

3 0

4 years ago

Can someone help me with b and c?

earnstyle [38]

$\bf \textit{Half-Angle Identities}
\\ \quad \\
sin\left(\cfrac{{{ \theta}}}{2}\right)=\pm \sqrt{\cfrac{1-cos({{ \theta}})}{2}}\qquad 
\boxed{cos\left(\cfrac{{{ \theta}}}{2}\right)=\pm \sqrt{\cfrac{1+cos({{ \theta}})}{2}}}$

$\bf tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}
\end{cases}\\\\
-----------------------------\\\\$

$\bf so\qquad 
\begin{cases}
2\cdot \cfrac{1}{8}\implies \cfrac{1}{4}\qquad thus\implies \cfrac{\frac{1}{4}}{2}\implies \cfrac{1}{8}\\\\
2\cdot \cfrac{1}{16}\implies \cfrac{1}{8}\qquad thus\implies \cfrac{\frac{1}{8}}{2}\implies \cfrac{1}{16}
\end{cases}\\\\
-----------------------------\\\\$

$\bf cos\left( \cfrac{\pi }{8} \right)\iff cos\left( \cfrac{\frac{\pi }{4}}{2} \right)
\\\\\\
cos\left( \cfrac{\frac{\pi }{4}}{2} \right)=\pm \sqrt{\cfrac{1+cos\left( \frac{\pi }{4} \right)}{2}}\implies \pm \sqrt{\cfrac{1+\frac{\sqrt{2}}{2}}{2}}\\\\
-----------------------------\\\\
cos\left( \cfrac{\pi }{16} \right)\iff cos\left( \cfrac{\frac{\pi }{8}}{2} \right)
\\\\\\
cos\left( \cfrac{\frac{\pi }{8}}{2} \right)=\pm \sqrt{\cfrac{1+cos\left( \frac{\pi }{8} \right)}{2}}$

and what is $\bf cos\left( \cfrac{\pi }{8} \right) \ ?$ well, you've just got it from the previous exercise :)

8 0

3 years ago