2 years ago

Help me asap

Mathematics

1 answer:

laila [671]2 years ago

7 0

Answer:

C. 3a is correct.

Step-by-step explanation:

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A 3 letter password from the letters a b c and d the password cannot have the same letter repeated in it how many such passwords

iren2701 [21]

Answer:

$24\ passwords$

Step-by-step explanation:

$Total\ available\ characters=4(a,b,c,d)\\\\ We\ want\ to\ choose\ 3\ of\ them.\\Here\ order\ matters\ (for\ example\ abc\ and\ acb\ are\ two\ different\ passwords) \\Hence\ we\ have\ to\ take\ permutation\ to\ count\ total\ possibilities.\\\\Total\ number\ of\ passwords=^4P_3\\\\Total\ number\ of\ passwords=\frac{4!}{(4-3)!}\\\\Total\ number\ of\ passwords=\frac{4!}{1!}\\\\Total\ number\ of\ passwords=24$

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3 years ago

Solve for x on this problem please

iren2701 [21]

Answer:

x = -3

Step-by-step explanation:

The LCD is 6, so multiply both sides by 6.

6[(3x + 1)/2] - 6[(4x - 3)/3] = 6 * 1

3(3x + 1) - 2(4x - 3) = 6

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x + 9 = 6

x = -3

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3 years ago

20 PTS!!!!!!!! HELPPP

Oksi-84 [34.3K]

Answer:

1. Not congruent

2. Not congruent

3. Congruent

4. Congruent

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6. Not congruent

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Step-by-step explanation:

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3 years ago

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Misha Larkins [42]

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2 years ago

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Inessa05 [86]

Answer:

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Step-by-step explanation:

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