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xenn [34]
3 years ago
14

PLS RESPOND ASAP 7th grade math

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

3/4

Step-by-step explanation:

The constant of proportionality is y/x

3/4

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Step-by-step explanation:

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Halla la medida del lado de un cuadrado cuya diagonal es de 14 cm​
8_murik_8 [283]

Answer:

The length side of the square is 7\sqrt{2}\ cm

Step-by-step explanation:

<u><em>The question in English is</em></u>

Find the measure of the side of a square whose diagonal is 14 cmd

Let

d ----> the diagonal of a square in cm

b ---> the length side of a square in cm

we know that

Applying the Pythagorean Theorem

see the attached figure to better understand the problem

d^2=b^2+b^2

d^2=2b^2

we have

d=14\ cm

substitute the given value

14^2=2b^2

solve for b

196=2b^2

98=b^2

take square root both sides

b=\sqrt{98}\ cm

simplify

b=7\sqrt{2}\ cm

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4 years ago
REwarding Brainliest to correct Answer
Scilla [17]

Answer:

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3 years ago
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Solve for x<br> (1/x) -2/3 = (4x)
Vadim26 [7]

The value of x is x=\frac{-1+\sqrt{37}}{12} and x=\frac{-1-\sqrt{37}}{12}

Step-by-step explanation:

The equation is \frac{1}{x}-\frac{2}{3}=4 x

Subtracting by 4x on both sides,

\frac{1}{x}-\frac{2}{3}-4 x=0

Taking LCM,

\frac{3-12 x^{2}-2 x}{3 x}=0

Multiplying by 3x on both sides,

-12 x^{2}-2 x+3=0

Dividing by (-) on both sides,

12 x^{2}+2 x-3=0

Using quadratic formula, we can solve for x.

\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}

Taking out common term 2, we get,

\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}

Thus, the value of x is  x=\frac{-1+\sqrt{37}}{12} and x=\frac{-1-\sqrt{37}}{12}

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3 years ago
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