Question

Evaluate the limit. Shown above

Answer 1

$\displaystyle\lim_{n\to\infty}\frac{6n^2+5}{3n^2}=\lim_{n\to\infty}2+\dfrac5{3n^2}$

As $n\to\infty$, the $\dfrac5{3n^2}$ term will converge to 0, so the limit is 2 (B).