Answer:
20n² - 40n + 20
Step-by-step explanation:
(5n - 5)(4n - 4)
= 5n(4n) + 5n(-4) - 5(4n) - 5(-4)
= 20n² - 20n - 20n + 20
= 20n² - 40n + 20
Another way to do this:
(5n - 5)(4n - 4)
= 5(n - 1) * 4(n - 1)
= 20(n - 1)(n - 1)
= 20(n - 1)²
= 20(n² - 2n + 1)
= 20n² - 40n + 20
Your answer will be 9.53 using the Tan = Opp/Adj formula
Answer: Choice A) at most 2.5 ft wide
Work Shown:
16w ≤ 40
w ≤ 40/16
w ≤ 2.5
This says that the banner must be at most 2.5 ft wide (choice A)
In other words, the largest the width can get is w = 2.5; we can think of this as the ceiling value.
