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olya-2409 [2.1K]
3 years ago
11

align="absmiddle" class="latex-formula">
Solve by completing the square. Please show work, I'm really struggling to understand this.
Mathematics
1 answer:
Ronch [10]3 years ago
5 0

Answer:

Step-by-step explanation:

x^2 - 22x = 10

Next step is to complete the square on the left hand side of the equation and it would be balanced by adding the same number to the right side of the equation. It becomes

x^2 - 22x + (22/2)^2 = 10 + (22/2)^2

x^2 - 22x + (11)^2 = 10 + (11)^2

x^2 - 22x + (11)^2 = 10 + 121

x^2 - 22x + (11)^2 = 131

x^2 - 22x + 121^2 = 131

(x - 11)^2 = 131

Taking square root of both the left hand side and the right hand side of the equation, it becomes

x - 11 = ±√131

x - 11 = ±11.45

Adding 11 to the left hand side and the right hand side of the equation, it becomes

x - 11 + 11 = ±11.45 + 11

x = 11.45 + 11 or x = -11.45 + 11

x = 22.45 or x = - 0.45

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<h3>Answer:   54</h3>

==============================================

Work Shown:

T = tens digit

U = units digit (aka ones digit)

A number like 27 is really 20+7 = 2*10 + 7*1 = 10*2 + 1*7. We have 2 in the tens digit and 7 in the units digit. So 27 can be written in the form 10T + U where T = 2 and U = 7. Reversing the digits gives 72, so T = 7 and U = 2 now. Clearly the difference between the digits 7 and 2 is not 1, so 27 or 72 is not the answer (as it's just an example).

-----------------------

Let T be larger than U. This doesn't work if T = U.

Because T is larger, saying "The difference between the digits is 1" means T - U = 1. We can isolate T to get T = U+1. We'll use this later.

-----------------------

If T > U, then the original number 10T+U reverses to the new number 10U+T and it becomes smaller. We are told that it becomes 5/6 of what it used to be.

So,

new number = (5/6)*(old number)

10U + T = (5/6)(10T + U)

6(10U + T) = 5(10T + U)

60U + 6T = 50T + 5U

60U + 6(U+1) = 50(U+1) + 5U ... plug in T = U+1

60U + 6U + 6 = 50U + 50 + 5U

66U + 6 = 55U + 50

66U - 55U = 50-6

11U = 44

U = 44/11

U = 4 is the units digit of the original number

T = U+1

T = 4+1

T = 5 is the tens digit of the original number

The original number is therefore 10T + U = 10*5+4 = 54.

We see the difference in their digits is T-U = 5-4 = 1

The reverse of 54 is 45. The number 45 is 5/6 of 54

45 = (5/6)*54

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