Please Help!!! What is the true solution to the equation below? 2log3(6x)-log3(4x)=2log3(x+2)
2 answers:
Answer:
x = 1 and x = 4
Step-by-step explanation:
A graph of the given equation, after rewriting to make the solutions be zeros of the function, shows the solutions to be x = 1 and x = 4.
You can take the antilog and solve the quadratic:
log3((6x)^2/(4x)) = log3((x+2)^2) . . . . consolidate the logs
9x = (x +2)^2 . . . . simplify and take the antilog
0 = x^2 -5x +4 . . . subtract 9x
0 = (x -4)(x -1) . . . . factor
Solutions are x = 1 and x = 4. (These values make the factors zero.)
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