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3 years ago

Please Help!!! What is the true solution to the equation below? 2log3(6x)-log3(4x)=2log3(x+2)

Mathematics

2 answers:

Vesna [10]3 years ago

5 0

Answer:

c on edge

Step-by-step explanation:

nikdorinn [45]3 years ago

4 0

Answer:

x = 1 and x = 4

Step-by-step explanation:

A graph of the given equation, after rewriting to make the solutions be zeros of the function, shows the solutions to be x = 1 and x = 4.

You can take the antilog and solve the quadratic:

log3((6x)^2/(4x)) = log3((x+2)^2) . . . . consolidate the logs

9x = (x +2)^2 . . . . simplify and take the antilog

0 = x^2 -5x +4 . . . subtract 9x

0 = (x -4)(x -1) . . . . factor

Solutions are x = 1 and x = 4. (These values make the factors zero.)

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A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

sattari [20]

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or $\frac{8}{12}$ ft

= $\frac{2}{3}$ ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= $\frac{11}{12}$ ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k( $\frac{2}{3}$ )

k = 18

Work done (W) to stretch the spring by $\frac{11}{12}$ ft will be

W = $\int\limits^\frac{11}{12} _0 {kx} \, dx$

= $\int\limits^\frac{11}{12} _0 {(18x)} \, dx$

= $18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0$

= 9( $\frac{11}{12}$ )²

= 7.56 lb-ft

6 0

3 years ago

CAN SOMEONE LLEASE HELP ME IM SO LOST!!

Afina-wow [57]

Answer: 1324 in^2

Step-by-step explanation:

4 0

3 years ago

Find the midpoint of line AB A) (4.5, 4.5) B) (1.5, 1.5) C) (3,3) D) (2,2)

cricket20 [7]

Answer:

B. (1.5, 1.5).

Step-by-step explanation:

Point A has coordinates (-3, -3) and point B is (6, 6).

The mid point is ((-3+6)/2 , (-3+6)/2)

= (3/2 , 3/2)

= (1.5, 1.5) (answer).

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3 years ago

Lauren drove 232 miles in 4 hours if she continued at the same rate how far would she travel in 15 hours

kompoz [17]

She would drive 870 miles in 15 hours

If you divide 232 by 4, you discover she travels 58 miles in one hour.

If you multiply 58 (the miles she drives in one hour) by 15 (the amount of hours) you get 870.

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3 years ago

56÷(7-9)^3 -24/23-5×4

yulyashka [42]

Answer:

= −28.043478261

Step By Step Explanation

Answer From Gauth Math

7 0

3 years ago

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