Question

Where on the graph of 2x - 6y = 7 is the x-coordinate twice the y-coordinate?

Answer 1

Answer:

The required point is P(-7,$\frac{-7}{2}$) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7

Step-by-step explanation:

Given equation of line is 2x-6y=7

To find point on graph whose x-coordinate twice the y-coordinate:

Let y be y-coordinate of point

Hence, x-coordinate of point will be 2y

The required point is P(2y,y) on equation of line 2x-6y=7

Now,

2x-6y=7

2(2y)-6y=7

-2y=7

y=$\frac{-7}{2}$

Thus,

The required point is P(-7,$\frac{-7}{2}$)

Note: Figure show equation of line red line and point P as blue dot.