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3 years ago

Can someone explain I’m confused ‍♂️

Mathematics

1 answer:

coldgirl [10]3 years ago

4 0

Answer:

x = 2000

y = 30000

y-intercept = 30000

slope = 15

one point = (2000 , 30000)

that is as far as I got. Sorry that I couldn't help more. :C

Step-by-step explanation:

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Help me answer for 11 points

Tcecarenko [31]

Answer:

Just Transposition...

Step-by-step explanation:

12×7=84=d

92-49=43=e

28+57=85=f

96÷16=6=g

11×8=88=h

95+5-29=100-29=71=I

55-6+21=70=j

88+8÷4=96÷4=16=k

19+24-97=-97-43=54=m

-20+17+61=61+3=64=n

hope it helps

4 0

3 years ago

HELP DUE IN 10 MINS! x =??

Black_prince [1.1K]

Answer:

x = 11

Step-by-step explanation:

Using Secants ad Segments Theorem we can say;

(x + 7) (7) = (15 + 6) (6)

7x + 49 = (21) (6)

7x + 49 = 126

7x = 77

x = 11

Hope this helps!

3 0

3 years ago

Read 2 more answers

Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

3 0

3 years ago

Solve for w. 8= 4 + w

Yuri [45]

W=4 that the answer !!!!!

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3 years ago

XYZ Toys makes a Feed-Me Baby Doll for $10.40. They mark up the cost by 55%. What is the selling price for the Feed-Me Baby Doll

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3 years ago