12 is your heckling my recking
Answer: 3x - 6 (in^2)
Step-by-step explanation:
base * height / 2
=
3 ( 2x - 4) / 2 (in^2)
= 3x - 6 (in^2)
Answer:
x = 5
Step-by-step explanation:
because the log is base 2 you can remove the log by raing 2 to the power of each side:
the 2 and log2 cancel leaving:
this means we can now solve through simple algebra:
Answer:
The area of ∆DEF = 4.5in²
Step-by-step explanation:
From the above diagram,
∆BAC ~∆DEF
It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides
This means for the above question, that
We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²
The small triangle has a side of 3in
Finding the scale factor k = ratio of the sides of both Triangles
k = 4/3
k² = (4/3)²
k² = 16/9
Hence,
Area of ∆BAC/ Area of ∆DEF = 16/9
8in²/Area of ∆DEF = 16/9
We cross Multiply
8 in² × 9 = Area of ∆DEF × 16
Divide both sides by 16
Area of ∆DEF = 72/16
= 4.5in²
Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²
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The image I saw was a paper with 90° edges. the 90° was cut into 2, 75° and x.
x = 90° - 75° = 15°
Interior angles of a triangle should equal 180°. The other corner of the paper is part of the triangle. It has a measure of 90°
The two angles are 15° and 90°. To find the remaining unknown angle, we deduct the two angles from 180°
3rd angle = 180° - 15° - 90°
3rd angle = 180° - 105°
3rd angle = 75°
