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2 years ago

Can someone double check my answer please !!

Mathematics

2 answers:

Brrunno [24]2 years ago

8 0

Answer:

ya its correct

Anuta_ua [19.1K]2 years ago

6 0

Answer:

Step-by-step explanation:

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An official NHL hockey puck is shaped like a cylinder with a diameter of 3 inches and a volume of 7.1 cubic inches. What is the

Dima020 [189]

H=1in

You would need to use the equation V= pie times radius squared times height. Since it gives you the diameter, you would need to divide 3 by 2 to get 1.5. So now you would plug in 7.1=pie×1.5(squared)×h

Now solve the equation to get 1in.

And you can check this answer by using this same equation to plug in pi×1.5 (squared)×1 and you will get 7.1 as your volume.

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3 years ago

Volume of composite figures

Feliz [49]

<u>✍️</u><u>Answer:</u>

The volume of the figure is 381 cubic in

$v=L*W*H$

$v=(16)(7)(3)+1/2(3)(5)(6)$

$v=336+45$

$v=381 in^3$

✮✮✮✮✮✮✮✮✮

<u>hope it helps...</u>

<u>have a great day!!</u>

7 0

2 years ago

Study time (hours)

xxTIMURxx [149]

Answer: A B and C

Step-by-step explanation:

I did the usatestprep

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2 years ago

Some steps to construct an angle MNT congruent to angle pqr

xxTIMURxx [149]

Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the afternoon drawn from N in a point

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2 years ago

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

6 0

2 years ago