Answer:
b and d
Step-by-step explanation:
Answer:
<em>(-6, 0) and (0, 1.5)</em>
<em></em>
Step-by-step explanation:
The equation of the line in pint slope form is expressed as;
y-y0= m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given
m = 1/4
(x0, y0) = (6,3)
Substitute into the formula;
y - 3 = 1/4(x-6)
4(y-3) = x - 6
4y - 12 = x-6
4y - x = -6+12
4y - x = 6
x = 4y - 6
To get the points to plot, we will find the x and y-intercept of the resulting expression.
For the x-intercept,
at y = 0
x = 4(0) - 6
x = -6
Hence the x-intercept is at (-6, 0)
For the y-intercept,
at x = 0
0 = 4y - 6
4y = 6
y = 6/4
y = 3/2
y = 1.5
Hence the y-intercept is at (0, 1.5)
<em>Hence the required points to plot to get the required line are (-6, 0) and (0, 1.5)</em>
<em></em>
The temperature on Tuesday afternoon is below 38 degrees Fahrenheit. As it states in the question the temperature on Tuesday morning was 27 degrees Fahrenheit and rose 10 more degrees at noon. Which makes is 37 degrees Fahrenheit at noon on Tuesday. You get this by taking 27 degrees and adding 10 degrees.
For this case we have to:
Given the quadratic equation of the form:

The roots are given by:

If we have: 
We can rewrite it in the following way:

Where:

Where we have:



By definition: 




Thus, the roots are given by imaginary numbers:

Answer:

Answer:
C
Step-by-step explanation: