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padilas [110]
3 years ago
7

Simplify there is a picture

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
2 to the power of 20/3 to the power of 8. 2^20/3^8 for short.
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Find the second derivative y=1/5x^2+1/11x
Amiraneli [1.4K]

\frac{dy}{dx}=\frac{1}{5}.x^{2-1}.2 + \frac{1}{11}.x^{1-1}.1

\frac{dy}{dx}=\frac{2}{5}.x+\frac{1}{11}

\frac{d^2y}{dx^2}=\frac{2}{5}.x^{1-1}.1

\frac{d^2y}{dx^2}=\frac{2}{5}

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a metal alloy weighing 3 mg and containing 40% copper is melted and mixed with 2 mg of pure copper. what percent of the resultin
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4 0
3 years ago
A standard number cube has 6 sides labeled 1 to 6. apu rolls a standard number cube 30 times. How many times can
Leviafan [203]

Answer:

The expected value of rolling a 5 or 6 is 10.

Step-by-step explanation:

The sample space of rolling a standard number cube is:

S = {1, 2, 3, 4, 5 and 6}

The cube is standard, this implies that each side has an equal probability of landing face-up.

So, the probability of all the six outcomes is same, i.e. \frac{1}{6}.

Now it is provided that Apu rolls the cube <em>n</em> = 30 times.

Let the random variable <em>X</em> represent the value on the face of cube.

The event of rolling a 5 and rolling a 6 are mutually exclusive, i.e. they cannot occur together.

So, P (X = 5 and X = 6) = 0.

Compute the probability of getting a 5 or 6 as follows:

P (X = 5 or X = 6) = P (X = 5) + P (X = 6) - P (X = 5 and X = 6)

                            = P (X = 5) + P (X = 6)

                            =\frac{1}{6}+\frac{1}{6}\\\\=\frac{2}{6}\\\\=\frac{1}{3}

Compute the expected value of rolling a 5 or 6 as follows:

E(X = 5\ \text{or}\ X = 6)=n\times P(X = 5\ \text{or}\ X = 6)

                               =30\times \frac{1}{3}\\\\=10

Thus, the expected value of rolling a 5 or 6 is 10.

8 0
3 years ago
Enter the number that belongs in the green box <br><br> PLEASE HELP FAST
ch4aika [34]
The answer in the green box should be 9.
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3 years ago
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