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2 years ago

Resuelve las siguientes ecuaciones: -x^2 - x =0 -X^2 + 12x = 0 3X^2 - 9x = 0 X^2 - 2x - 3 = 0

Mathematics

1 answer:

vaieri [72.5K]2 years ago

4 0

Responder:

a) 1

b) 12

c) 3

d) -1 y 3

Explicación paso a paso:

Dadas las siguientes ecuaciones;

a) x²-x =0

x² = 0+x

x² = x

x = 1

b) -x²+12x = 0

-x² = -12x

x² = 12x

x = 12

c) 3x² - 9x = 0

Suma 9x a ambos lados

3x²-9x+9x = 0+9x

3x² = 9x

3x = 9

x = 9/3

x = 3

d) x²-2x-3 = 0

x²-3x+x-3 = 0

x(x-3)+1(x-3) = 0

(x+1)(x-3) = 0

x+1 = 0 y x-3 = 0

x = -1 y 3

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Answer:

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Step-by-step explanation:

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Simplify

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7 0

3 years ago

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In triangle XYZ, let angle Y be a right angle, mZ = 54°, and YZ = 361. Find the area of the

laiz [17]

Answer:

89,709

Step-by-step explanation:

∡Z= 54°

tan 54 = XY / 361

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2 years ago

F(x) = x2 + 1 g(x) = 5-x (f+g)(x) = O x2 + x-4 x²+x+4 O x2-x+6 O x2 + x + 6

charle [14.2K]

Answer:

$\boxed{(f + g)(x) = {x}^{2} - x + 6}$

Given:

$f(x) = {x}^{2} + 1 \\ \\ g(x) = 5 - x$

To Find:

$(f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$= > f(x) + g(x) = ({x}^{2} + 1) + (5 - x) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 1 + 5 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 6 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - x + 6$