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kompoz [17]
3 years ago
13

Case Study 1: What went good and what went bad in the lab scenario?

Chemistry
2 answers:
user100 [1]3 years ago
8 0
The good:
•Jane was using a beaker,
•she had been told to make all observations that she could which is good because that means she was listening to the teacher
The bad:
•Jane was mixing two chemicals
• she smelled the gas
Anettt [7]3 years ago
6 0

Answer:

Nothing went well.  

Explanation:

Everything went badly.

  1. Jennifer took off her goggles. The mixture was already bubbling. It could have suddenly spurted into her hands and face.
  2. She took a good whiff of the greenish-yellow gas (chlorine?). She should have held the beaker some distance away and gently wafted some of the gas toward her nose.

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If the force produced by the engine is 3400 N to the right and the force caused by friction is 400 N to the left, what is the NE
lisov135 [29]

Answer:

2400/400

Explanation:

6 0
3 years ago
Read 2 more answers
Why should you add acid to water rather than add water to acid when preparing solutions?.
victus00 [196]

Answer:It is because acid and water react violently exothermically, producing heat and occasionally melting the fluid.

Explanation:

7 0
3 years ago
What are the products of the acid-base reaction between HNO3 and NaOH? A. H2O and NaNO3 B. NaH and NO3OH C. HNOH and NaO3 D. NaO
Otrada [13]

Answer:- A. H_2O and NaNO_3

Explanations:- In general, acid+base\rightarrow salt+water

In acid-base reaction the acid gives hydrogen ion and the base gives hydroxide ion and these ions combine to form water. Rest of the ions from acid and base combine to form the salt.

Nitric acid breaks to give hydrogen ion and nitrate ion. Similarly, NaOH breaks to give sodium ion and hydroxide ion. Since, hydrogen ion and hydroxide ions form water, the sodium ion and nitrate ion forms the salt, sodium nitrate.

The reaction is shown as:

HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)

So, the right choice is A.

5 0
3 years ago
A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution
Marianna [84]

Answer:

0.136g

Explanation:

A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?

Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)

Initial mole of Co(NO3)2  =\frac{mass}{molar mass}

=\frac{5.00}{182.94} \\\\=0.02733mol

Mole of Co(NO3)2 in final solution

=\frac{4.00}{100}\times 0.02733\\\\=0.04\times 0.02733\\\\= 0.001093mol

Mole of  NO3- in final solution = 2 x Mole of Co(NO3)2

=2\times 0.001093\\\\=0.002186mol

Mass of  NO3- in final solution is mole x Molar mass of NO3

=0.002186\times62.01\\\\=0.136g

6 0
4 years ago
Calculate the volume in liters of a M barium chloride solution that contains of barium chloride . Round your answer to significa
Reptile [31]

Answer:

1.667L of a 0.30M BaCl₂ solution

Explanation:

<em>Of a 0.30M barium chloride, contains 500.0mmol of barium chloride.</em>

<em />

Molarity is an unit of concentration used in chemistry defined as the moles of solute present in 1 liter of solution.

In a 0.30M BaCl₂ solution there are 0.30 moles of BaCl₂ in 1 liter of solution.

Now, in your solution you have 500mmol of BaCl₂ = 0.500 moles of BaCl₂ (1000 mmol = 1 mol). Thus, 0.500 moles of BaCl₂ are present in:

0.500 moles * (1L / 0.30 moles) =

<h3>1.667L of a 0.30M BaCl₂ solution</h3>
5 0
3 years ago
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